# Numerical Expressions Involving Decimal Numbers

Here we will discuss numerical expressions involving decimal numbers. we know that in numerical expressions we have to perform various operations like addition, subtraction, multiplication and division in one sum following the BODMAS rule. This BODMAS stands for brackets, of, division, multiplication, addition and subtraction.

Here are few examples shown following the BODMAS rule:

1. 1.2 ÷ 0.6 of 3.5 × 2.1 – 1.1 + 0.25

Solution:

1.2 ÷ 0.6 + 3.6 × 2.1 – 1.1 + 0.25

= 2 + 3.6 × 2.1 – 1.1 + 0.25

= 2 + 7.56 – 1.1 + 0.25

= 9.56 – 1.1 + 0.25

= 9.56 + 0.25 – 1.1

= 9.81 – 1.1

= 8.71

Explanation:

We will first divide (i.e. 1.2/0.6) leaving the other operations as it is. Then we will multiply i.e. 3.6 multiplied by 2.1. Then we have are left with addition and subtraction. So we will first do addition and then subtraction.

2. 4.5 + 5.6 ÷ 0.8 + 7.56 – 2.53

Solution:

4.5 + 5.6 ÷ 0.8 + 7.56 – 2.53

= 4.5 + 7 + 7.56 – 2.53

= 19.06 – 2.53

= 16.53

Explanation:

We will first divide (i.e.5.6/0.8 to get 7) then we will do addition (I.e. 4.5 + 7 + 7.56 to get 19.06) and lastly subtraction (i.e. 19.06 – 2.53 to get 16.53) according to the BODMAS rule.

3. 2.2 × 5.4 + 6.36 – 7.10 × 0 + 3.56

Solution:

2.2 × 5.4 + 6.36 – 7.10 × 0 + 3.56

= 11.88 + 6.36 – 0 + 3.56

= 11.88 + 6.36 + 3.56 – 0

= 21.80 – 0

= 21.80

Explanation:

First 2.2 multiplied by 5.4 and 7.10 multiplied by 0. After getting the answer of two multiplications we are left with only addition and subtraction. For addition we will arrange the numbers that are to be added together and then add them and finally with that result we subtracted 0 from it.

4. 8.5 ÷ 0.5 + 6.58 – 5.54 × 0.62 + 23.25

Solution:

8.5 ÷ 0.05 + 6.58 – 5.54 × 0.62 + 23.25

= 170 + 6.58 – 5.54 × 0.62 + 23.25

= 170 + 6.58 – 3.4348 + 23.25

= 170 + 6.58 + 23.25 – 3.4348

= 199.83 – 3.4348

= 196.3952

Explanation:

At first 8.5 is divided by 0.05 to get 170 and then perform the multiplication (i.e. 5.54 multiplied by 0.62) and then will be left with addition and then subtraction according to BODMAS.

5. 7.8 + 3.6 – 2.3 × 0 + 4.9 of 7 ÷ 5.6

Solution:

7.8 + 3.6 – 2.3 × 0 + 4.9 of 7 ÷ 5.6

= 7.8 + 3.6 – 2.3 × 0 + 34.3 ÷ 5.6

= 7.8 + 3.6 – 2.3 × 0 + 6.125

= 7.8 + 3.6 – 0 + 6.125

= 7.8 + 3.6 + 6.125

= 17.525

Explanation:

Firstly 4.9 of 7 is done ‘of’ actually multiplication. Then the result 34.3 is divided by 5.6 9.8 to get 6.125 and in the next step 2.3 is multiplied by 0 to get 0 and at the end all the three (7.8, 3.6, 2) are added to get the final result.

## You might like these

• ### Worksheet on Divisibility Rules | Questions on Test of Divisibility

This is a worksheet which will provide few problems on the divisibility rule of 2, 3, 4, 5, 6, 7, 8, 9, and 10. 1. Check whether the following numbers are divisible by 2 or 3 or both? (i) 2562 (ii) 5693 (iii) 2201 (iv) 7480 (v) 5296 (vi) 4062 (vii) 4568 (viii) 1425 (ix) 1110

• ### Problems on Divisibility Rules | Rules to Test of Divisibility | Test

Here are few problems on the divisibility rules of 2, 3, 4, 5, 6, 7, 8, 9, and 10 which will help the learners in revising their concepts on the divisibility rules. 1. Check whether 3456 is divisible by 2? Solution: The last digit is an even number (i.e. 6) hence 3456 is

## Recent Articles

1. ### Respiratory Balance Sheet | TCA Cycle | ATP Consumption Process

Feb 18, 24 01:56 PM

The major component that produced during the photosynthesis is Glucose which is further metabolised by the different metabolic pathways like glycolysis, Krebs cycle, TCA cycle and produces energy whic…

2. ### Electron Transport System and Oxidative Phosphorylation | ETC |Diagram

Feb 04, 24 01:57 PM

It is also called ETC. Electron transfer means the process where one electron relocates from one atom to the other atom. Definition of electron transport chain - The biological process where a chains…

3. ### Tricarboxylic Acid Cycle | Krebs Cycle | Steps | End Products |Diagram

Jan 28, 24 12:39 PM

This is a type of process which execute in a cyclical form and final common pathway for oxidation of Carbohydrates fat protein through which acetyl coenzyme a or acetyl CoA is completely oxidised to c…

4. ### Aerobic Respiration | Definition of Aerobic Respiration | Glycolysis

Dec 15, 23 08:42 AM

This is a type of respiration where molecular free oxygen is used as the final acceptor and it is observed in cell. Site of Aerobic Respiration - Aerobic respiration is observed in most of the eukaryo…