Divisible by 3
This topic is on the divisibility rule of 3 and few examples based on the topic.
If the sum of the digits is divisible by 3 then the whole number is divisible by 3.
For example 519
The sum of the digits = 5 + 1 + 9 = 15
15 is divisible by 3 hence 519 is also divisible by 3
Here are few examples on the divisibility rule of 3
1. Check whether the following numbers are divisible by 3 or not?
(i) 789
(ii) 451
(iii) 322
(iv) 410
(v) 561
(vi) 111
(vii) 327
(viii) 848
(ix) 450
(x) 356
Solution:
(i) 789
Sum of the digits = 7 + 8 + 9 = 24
24 is divisible by 3 hence 789 is divisible by 3
(ii) 451
Sum of the digits = 4 + 5 + 1 = 10
10 is not divisible by 3 hence the number is also not divisible by 3
(iii) 322
Sum of the digits = 3 + 2 + 2 = 7
322 is not divisible by 3 as 7 is not divisible by 3
(iv) 410
Sum of the digits = 4 + 1 + 0 = 5
5 is not divisible by 3 hence 410 is also not divisible by 3
(v) 561
Sum of the digits = 5 + 6 + 1 = 12
561 is divisible by 3 as 12 is divisible by 3
(vi) 111
Sum of the digits = 1 + 1 + 1 = 3
3 is divisible by 3 hence 111 is also divisible by 3
(vii) 327
Sum of the digits = 3 + 2 + 7 = 12
327 is divisible by 3 as 12 is divisible by 3
(viii) 848
Sum of the digits = 8 + 4 + 8 = 20
20 is not divisible by 3 hence 848 is also not divisible by 3
(ix) 450
Sum of the digits = 4 + 5 + 0 = 9
9 is divisible by 3 hence 450 is also divisible by 3
(x) 356
Sum of the digits = 3 + 5 + 6 = 14
356 is not divisible by 3 as 14 is not divisible by 3
2. Fill in the blanks to make the numbers divisible by 3.
(i) 6 …. 7
(ii) 4 …. 0
(iii) …. 75
(iv) 2 …. 6
(v) …. 33
(vi) 40 ….
(vii) 7 …. 3
(viii) 5 …. 6
(ix) …. 11
(x) 9 …. 0
Solution:
() 627
(ii) 480
(iii) 675
(iv) 216
(v) 333
(vi) 405
(vii) 753
(viii) 516
(ix) 111
(x) 900
Explanation:
The numbers should be filled in such a way that the sum of the digits is divisible by 3.
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