# Divisible by 3

This topic is on the divisibility rule of 3 and few examples based on the topic.

If the sum of the digits is divisible by 3 then the whole number is divisible by 3.

For example 519

The sum of the digits = 5 + 1 + 9 = 15

15 is divisible by 3 hence 519 is also divisible by 3

Here are few examples on the divisibility rule of 3

1. Check whether the following numbers are divisible by 3 or not?

(i) 789

(ii) 451

(iii) 322

(iv) 410

(v) 561

(vi) 111

(vii) 327

(viii) 848

(ix) 450

(x) 356

Solution:

(i) 789

Sum of the digits = 7 + 8 + 9 = 24

24 is divisible by 3 hence 789 is divisible by 3

(ii) 451

Sum of the digits = 4 + 5 + 1 = 10

10 is not divisible by 3 hence the number is also not divisible by 3

(iii) 322

Sum of the digits = 3 + 2 + 2 = 7

322 is not divisible by 3 as 7 is not divisible by 3

(iv) 410

Sum of the digits = 4 + 1 + 0 = 5

5 is not divisible by 3 hence 410 is also not divisible by 3

(v) 561

Sum of the digits = 5 + 6 + 1 = 12

561 is divisible by 3 as 12 is divisible by 3

(vi) 111

Sum of the digits = 1 + 1 + 1 = 3

3 is divisible by 3 hence 111 is also divisible by 3

(vii) 327

Sum of the digits = 3 + 2 + 7 = 12

327 is divisible by 3 as 12 is divisible by 3

(viii) 848

Sum of the digits = 8 + 4 + 8 = 20

20 is not divisible by 3 hence 848 is also not divisible by 3

(ix) 450

Sum of the digits = 4 + 5 + 0 = 9

9 is divisible by 3 hence 450 is also divisible by 3

(x) 356

Sum of the digits = 3 + 5 + 6 = 14

356 is not divisible by 3 as 14 is not divisible by 3

2. Fill in the blanks to make the numbers divisible by 3.

(i) 6 …. 7

(ii) 4 …. 0

(iii) …. 75

(iv) 2 …. 6

(v) …. 33

(vi) 40 ….

(vii) 7 …. 3

(viii) 5 …. 6

(ix) …. 11

(x) 9 …. 0

Solution:

() 627

(ii) 480

(iii) 675

(iv) 216

(v) 333

(vi) 405

(vii) 753

(viii) 516

(ix)  111

(x) 900

Explanation:

The numbers should be filled in such a way that the sum of the digits is divisible by 3.

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